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The vehicle accelerates horizontally from rest to 27.8 m s–1 in a time of 4.6 s. The mass of the vehicle is 360 kg and the rider has a mass of 82 kg. 1. Calculate the average acceleration during the 4.6 s time interval.

This question is testing your ability to recognise which equations to use from the formula sheet based on the variables provided.

To start, write down the known variables in the SUVAT fr...

Answered by Zaid A. • Physics tutor

7369 Views

State 2 factors that affect the centripetal force for a object having a circular path.

Answer: Can be any 2 of mass, velocity or radius of path.

The formula for the centripetal force (resultant) acting F=m(v^2)/r. Therefore the variables are mass, velocity for the object ...

Answered by Winston M. • Physics tutor

15614 Views

A 0.20 kg mass is whirled round in a vertical circle on the end of a light string of length 0.90 m. At the top point of the circle the speed of the mass is 8.2 m/s. What is the tension in the string at this point?

A diagram would be very beneficial for this problem. We can draw a free body force diagram of the mass. At the top of the circle the two forces acting on it are its weight and tension from the string. Bot...

Answered by Thomas C. • Physics tutor

49259 Views

If a cricket ball of mass 500g is thrown upwards from the ground with an initial velocity of 20 m/s, how high will the ball reach?

The best method of answering this question would be to look at the energy of the ball at the moment it is thrown and at the moment it reaches its highest point.
When the ball is thrown, initially all...

Answered by Thomas C. • Physics tutor

12258 Views