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1. Identify that we are looking at dy/dx, not dx/dy and realise the relationship that dy/dx=1/(dx/dy)2)Try find dx/dy;cot = 1/tan or (tan)^-1Hence, x=(tan y )^-1 implying dx/dy = (-...

y=x^2-x-2y=(x+1)(x-2)The gradient (dy/dx) measures the rate of the change in y with respect to x. So this can be used to help us find the gradient of a function at any point along it. The question asks th...

This is when a company's costs decrease as a result of increased production. This may occur when two companies decide to merge in order to grow the business by pooling their individual resources. As a res...

Factorising is all about writing algebraic expressions using brackets, to separate x terms.(x + ... )(x +... ) when multiplying out the brackets there will be an x² term, an x term and a numeri...

Firstly we write down all known variables: Initial speed (u)=0 m/s, Acceleration (a)=3 m/s², Time (t)=5s. Final velocity (v)=?Therefore, the equation chosen to solve the problem would be: v=u+a...