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subtract one from the other to eliminate y: 3x+y=11; 2x+y=8 --> x=3substitute value of x back in and solve for y: 3(3)+y=11; 9+y=11; --> y=2
(a) Remember: Multiply each term in the left bracket by every term in the right bracket.(x-3)(x+5) = x2+ 5x - 3x -15.Collecting all of the like terms:= x2+ 2x -15.(b) Solve xJWAnswered by Jack W. • Maths tutor8896 Views
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