Why does d/dx (tan(x)) = sec^2(x)?

This result comes from using a trig identity and the quotient rule. First, we write tan(x) as sin(x)/cos(x). Then we apply the quotient rule. After doing the standard derivatives, the numerator of our fraction becomes another trig identity, sine squared + cosine squared, which equals one. Now, looking at our fraction, we can see we have 1/cos^2(x). We can then rewrite this as (1/cos(x))^2. We apply our final trig identity now, 1/cos(x)=sec(x), and we see that d/dx tan(x) = sec^2(x). (Due to the nature of writing mathematics, this is far easier to represent and explain using the whiteboard)

TD
Answered by Tutor42661 D. Maths tutor

11576 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A circle has the equation x^2 + y^2 - 4x + 10y - 115 = 0. Express the equation in the form (x - a)^2 + (y - b)^2 = k, and find the centre and radius of the circle.


How do you find the possible values of cos(x) from 5cos^2(x) - cos(x) = sin^2(x)?


integrate 1/(x^2+4x+13)


How do you find the gradient of a line at a certain point when f(x) is in the form of a fraction, where both the numerator and denominator are functions of x?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning