Why does d/dx (tan(x)) = sec^2(x)?

This result comes from using a trig identity and the quotient rule. First, we write tan(x) as sin(x)/cos(x). Then we apply the quotient rule. After doing the standard derivatives, the numerator of our fraction becomes another trig identity, sine squared + cosine squared, which equals one. Now, looking at our fraction, we can see we have 1/cos^2(x). We can then rewrite this as (1/cos(x))^2. We apply our final trig identity now, 1/cos(x)=sec(x), and we see that d/dx tan(x) = sec^2(x). (Due to the nature of writing mathematics, this is far easier to represent and explain using the whiteboard)

TD
Answered by Tutor42661 D. Maths tutor

10677 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Relative to a fixed origin O, the point A has position vector (8i+13j-2k), the point B has position vector (10i+14j-4k). A line l passes through points A and B. Find the vector equation of this line.


integrate xcosx


Find tan(A-B) sec^2(A) - 2tan(A) = 16 && sin(B)sec^2(B) = 64cos(B)cosec^2(B)


Find the vertex coordinates of parabola y = 2x^2 - 4x + 1


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning