find dy/dx of the equation y=ln(x)2x^2
Here it is necessary to use the chain rule to solve the derivative. If we equate our equation in terms of the following notation: ln(x)='u'and 2x^2='v' and use the chain rule formula dy/dx=udv/dx+vdu/dx we can solve the derivative:
= lnx(4x)+(2x^2)(1/x) = 4xlnx+2x
PG
Related Maths A Level answers
All answers ▸How do you find the turning points of a curve described by the equation y(x)?
given that at a time t, a particle is accelerating in the positive x-direction at 1/t ms^-2, calculate the velocity and the displacement of the particle at time t = 2s
Integrate (3x^2-x^3)dx
Integrate x * sin(x) with respect to x by using integration by parts