Differentiate, y = 2x^3 + 2/x + 3
Differentiate by multiply by the power and then minus 1 from the power. Use the rule: y= ax^b -> dy/dx = abx^(b-1)
dy/dx = 3 x 2x^(3-1) + -1 x 2x^(-1-1) + 0 dy/dx = 6x^2 - 2x^-2
CH
Related Maths A Level answers
All answers ▸Solve the equation x^6 + 26x^3 − 27 = 0
When you integrate, why do you need to add a +C on the end?
Find the values of x for which f(x) is an increasing function given that f(x)=8x-2x^2
Using the addition formula for sin(x+y), find sin(3x) in terms of sin(x) and hence show that sin(10) is a root of the equation 8x^3 - 6x + 1