Differentiate, y = 2x^3 + 2/x + 3

Differentiate by multiply by the power and then minus 1 from the power. Use the rule: y= ax^b -> dy/dx = abx^(b-1)

dy/dx = 3 x 2x^(3-1) + -1 x 2x^(-1-1) + 0 dy/dx = 6x^2 - 2x^-2

CH
Answered by Claudia H. Maths tutor

4162 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

find dy/dx for the equation y = 6x ^(1/2)+x+3


Find the derivative and following function and hence find the value of coordinates for when the function is at a stationary point:


A curve has the equation y = 2x cos(3x) + (3x^2-4) sin(3x). Find the derivative in the form (mx^2 + n) cos(3x)


Find the gradient of y^2 +2xln(y) = x^2 at the point (1,1)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning