expand and simplify (x+3)(x-7)

(x+3)(x-7)

= (xx) + (x-7) + (x3) + (3-7)

= x^2 - 7x + 3x - 21

= x^2 - 4x - 21

Key here is to ensure you multiply each term in one bracket by both in the other, and to keep careful track of the signs.

LP
Answered by Luke P. Maths tutor

25427 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

How do you solve the quadratic equation x^2+7x+12=0


√5( √8 +√18) can be written in the form a√10 where a is an integer.


How Would I Factorise A Quadratic Equation?


The area of a square is 49cm^2. The perimeter of this square is equal to the circumference of a circle. Calculate the radius of the circle to 1 decimal place.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning