For y = 7x - x^3, find the two stationary points and what type of stationary points they are.
Differentiate y to get: dy/dx = 7-3x^2 , dy/dx = 0 , therefore x=(+/-)sqrt(7/3) d^2y/dx^2 = 6x , substitute x values in to y=7x-x^3 and d^2y/dx^2 to find coordinates and the type of the stationary point.
RS
Related Maths A Level answers
All answers ▸Differentiate the function f(x)=2xsin3x
Given (x-2) is a factor of ax^3 + ax^2 + ax - 42, find the value of a
Given that y = 16x + x^-1, find the two values of x for which dy/dx = 0
The expansion of (1+x)^4 is 1 + 4x +nx^2 + 4x^3 + x^4. Find the value of n. Hence Find the integral of (1+√y)^4 between the values 1 and 0 (one top, zero bottom).