For y = 7x - x^3, find the two stationary points and what type of stationary points they are.

Differentiate y to get: dy/dx = 7-3x^2 , dy/dx = 0 , therefore x=(+/-)sqrt(7/3) d^2y/dx^2 = 6x , substitute x values in to y=7x-x^3 and d^2y/dx^2 to find coordinates and the type of the stationary point.

RS

Related Maths A Level answers

All answers ▸

Find the equation of the tangent at x=1 for the curve y=(4x^2+1)^3


What is differentiation and integration?


How do I find the turning points of a curve?


A curve has equation y = (x-1)e^(-3x). The curve has a stationary point M. Show that the x-coordinate of M is 4/3.