Differentiate y = (6x-13)^3 with respect to x

We are looking for dy/dx, and in this question, the key rule to remember is the chain rule.

Therefore the first thing to do is the easy step, take the 3 down and minus 1 from it, this will give 3(6x-13)2.  But this is not the final answer as we have not also differentiated what is inside the bracket, hence we need to differentiate (6x-13), which is just 6, so we multiply this by the whole equation.

Therefore our answer will become 6*3(6x-13)= 18(6x-13)2

TS
Answered by Toby S. Maths tutor

5912 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve is defined by the parametric equations x = 3 - 4t, and y = 1 + 2/t. Find dy/dx in terms of t.


The point on the circle x^2+y^2+6x+8y = 75 which is closest to the origin, is at what distance from the origin? (Taken from an MAT paper)


Express 5cosx - 3sinx in the form Rcos(x+a).


Given x=Sqrt(3)sin(2t) and y=4cos^2(t), where 0<t<pi. Show that dy/dx = kSqrt(3)tan(2t).


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning