Rearrange, 5(a + b)= 2ab , to make 'a' the subject

The question is asking for 'a' to be the subject and therefore our aim is to result in an answer with the form 'a='. The first step is to expand the brackets on the left hand side by multiplying 'a' by 5 and then 'b' by 5 to result with 5a + 5b= 2ab. Now that we want to make 'a' the subject we need to reaarange the equation such that all the 'a' terms are on one side and the 'b' terms on the other. By minusing '5a' from both sides of the equation (as we have to do the same to both sides) we end up with the equation: 5b= 2ab - 5a. As there are two 'a' terms on the right hand side we are now able to factorise and do the opposite to what we did in the first step. By removing the common 'a' from both terms and introducing brackets we end up with 5b= a(2b-5). The final step to this question is to make 'a' the subject. By dividing both sides by '2b-5' we can move the '2b-5' to the left hand side and leave 'a' to be the subject. This will give us the final answer of a= 5b/ 2b-5. This question is most likely worth 3 or 4 marks and therefore inclusion of every step is key to ensure you gain all the marks!

MM
Answered by Meera M. Maths tutor

9846 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

For the curve C with equation y = x4 – 8x2 + 3. Find dy/dx


N sweets in a bag. 6 sweets are orange. The rest are yellow. Hannah takes a random sweet from the bag and eats it. She then takes another random sweet from the bag & eats it. The probability Hannah eats 2 orange sweets is 1/3. Show n^2 - n - 90 = 0.


Expand 5yx^2 (3x^3 - 5xy + wy^2)


Why is it that when I am asked to factorise 3x^2-13x-10, I am not able to cancel two of the x's so that the answer is 3x-13-10?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning