Find the intersection points between the graphs y=2x+5 and y=x^2-9.
To do this, first draw a sketch of both graphs to see roughly what kind of result we should expect to get. We know that at the intersection points, the values of x and y for both graphs must be equal. so set both graphs equal to each other and we get
2x+5=x^2-9
rearranging this equation we then get
0=x^2-2x-14
We then use the quadratic formula to get values for x, for which you get
x=1+squ. root(15) and x=1- squ. root(15) . (sorry i didn't know how to insert squ. root symbol)
we then substitute both values into either equation (since we're looking at intersection points) and we get
y=7+ 2squ root(15) and y=7-2squ root(15).
SB
Related Maths A Level answers
All answers ▸Find the general solution, in degrees, of the equation 2sin(3x+45°)=1. Use your general solution to find the solution of 2sin(3x+45°)=1 that is closest to 200 °.
Using the substitution u = 2 + √(2x + 1), or other suitable substitutions, find the exact value of 4 0 1 ∫ 2 (2 1) +√ +x dx giving your answer in the form A + 2ln B, where A is an integer and B is a positive constant
Suppose a population of size x experiences growth at a rate of dx/dt = kx where t is time measured in minutes and k is a constant. At t=0, x=xo. If the population doubles in 5 minutes, how much longer does it take for the population to reach triple of Xo.
What is integration?