How to differentiate y=(x^2+4x)^5

To differentiate y=(x2+4x)5 you need to use the chain rule. The chain rule uses the fact that dy/dx = dy/dt * dt/dx. 

Here we create a new variable t, where t = x2+4x. Substituting this in the original equation gives y=t5

Differentiating t=x2+4x with respect to x; dt/dx = 2x+4

Differentiating y=t5 with respect to t; dy/dt = 5t4

We can combine these two equations to find dy/dx, as the chain rule states dy/dx = dy/dt * dt/dx.

This gives dy/dx = 5t4*(2x+4)

Substituting in our value of t, gives the final answer dy/dx = 5(x2+4x)4(2x+4)

AM
Answered by Alexandra M. Maths tutor

6454 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How does integration work?


Using Discriminants to Find the Number of Roots of a Quadratic Curve


How do you differentiate a function comprised of two functions multiplied together?


differentiate y = 4x^3(12e^-4x) with respect to x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences