Solve x^3=1 giving all the roots between -pi<=theta<=pi in exponential form

 x^3=1=e^2(pi)i

x=e^2(pi)ik/3

The three roots are

k=0    x=1 

k=1    x=e^2(pi)*i/3

k=-1   x=e^-2(pi)ik/3

AA
Answered by Anmol A. Further Mathematics tutor

3456 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Given that α= 1+3i is a root of the equation z^3 - pz^2 + 18z - q = 0 where p and q are real, find the other roots, then p and q.


Write the Maclaurin’s series for f(x)=sin(3x)+e^x up to the third order


What are imaginary numbers, and why do we bother thinking about them if they don't exist?


MEI (OCR) M4 June 2006 Q3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning