titration calculation: 35cm3 of Hydrochloric Acid reacts with 27.5cm3, 0.3mol/dm3 NaOH. What is the Concentration of the Hydrochloric Acid?
- Write out what you know:
HCL - VOL: 35 --- CONC: (x) --- MOL: (x)
NaOH - VOL: 27.5 --- CONC: 0.3 --- MOL: (x)
- Realise what you can work out - Mol of NaOH in this case
Mol = Conc x (Vol/1000)
so Mol = 0.3 x (27.5/1000)
Mol = 0.00825
- Now you have all the Info for one substance and most importantly the moles of a substance.
- Mol Ratio is 1:1 unless the question says otherwise
- Rearrange Mol = Conc x (Vol/1000)
to make Conc = Mol / (Vol/1000)
Conc = 0.00825 / (35/1000)
Conc = 0.235
0.24mol/dm3 = Conc of HCL
GK
Related Chemistry GCSE answers
All answers ▸Describe the relationship between the number of carbon atoms in an alkane molecule and its boiling point.
Describe how ionic and covalent bonding forms compounds (6). You may use diagrams to help.
Describe how elements of the periodic table are arranged relating to their atomic structure. (6 marks)
Using collision theory, explain why increasing the concentration of a reactant increases the rate of reaction.