Find ∫ x^2(ln(4x))dx

 ∫xln(4x)dx

Firstly , identify this question as integration by parts. Therefore set one half as value 'u' and one as value 'dv'.

Here we will set u = ln(4x).

Therefore: du/dx = 1/4x . (4)        

                       du = 1/x dx                 We then set dv = x2 dx                                                          

                                                                          dv/dx = x2                                                              

                                                                                v = x3/3

The formula for integration by parts is :

u.v -  ∫v.du

= ln(4x).(x3) -  ∫(x3/3)(1/x)dx

= x3ln(4x) - ∫(x2/3)dx

= x3ln(4x) - x3/9 + c

SF
Answered by Sally F. Maths tutor

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