What is the turning point on the curve f(x) = 2x^2 - 2x + 4

df/dx = 4x - 2

turning point when differential = 0 

==>

4x = 2 hence;  x = 0.5

When x = 0.5 f(x) is equal to (substitute) 3.5

hence the turning point is at (0.5,3.5)

DT
Answered by David T. Maths tutor

5368 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How would you integrate ln x


Given that y = (( 4x + 1 )^3)sin(2x), find dy/dx.


A curve has the equation y = x^4 - 8x^2 + 60x + 7. What is the gradient of the curve when x = 6?


Given that 2-3i is a root to the equation z^3+pz^2+qz-13p=0, show that p=-2 and q=5.


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences