What is the turning point on the curve f(x) = 2x^2 - 2x + 4

df/dx = 4x - 2

turning point when differential = 0 

==>

4x = 2 hence;  x = 0.5

When x = 0.5 f(x) is equal to (substitute) 3.5

hence the turning point is at (0.5,3.5)

DT

Related Maths A Level answers

All answers ▸

Find the gradient of the curve y=sin(x^2) + e^(x) at the point x= sqrt(pi)


Given that y= 1/ (6x-3)^0.5 find the value of dy/dx at (2;1/3)


Differentiate 5x^2 + 11x + 5 with respect to x


The point P lies on the curve C: y=f(x) where f(x)=x^3-2x^2+6x-12 and has x coordinate 1. Find the equation of the line normal to C which passes through P.