Find the equation of a straight line that passes through the coordinates (12,-10) and (5,4). Leaving your answer in the form y = mx + c

Finding the gradient (m): The gradient is the change in y-axis over the change in x-axis Δy = -10-4= -14        Δx = 12-5=7 Δy/Δx = -14/7 = -2 Accumilating the equation: The equation of a straight line can be deduced by a simple formula y- ya = m(x- xa)      where a is a coordinate which lies on the lie.

The equation: y - 4 = -2(x - 5) y - 4 = -2x + 10

Therefore the equation of the line: y= -2x+14

MM
Answered by Martin M. Maths tutor

8411 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do you integrate (x/(x+1)) dx without using substitution.


What are the solutions of (x^3)+6 = 2(x^2)+5x given x = 3 is a solution?


What is the Product Rule?


Find dy/dx if y=(x^3)(e^2x)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences