How do you find the gradient of a straight line?

The gradient of a straight line is the number before the x if it is in the form y=mx+c. So for y=6x+2 the gradient is 6. If the y has a factor, like 2y=6x+2, then you have to divide everything by the factor to get just y=, so the equation would be y=3x+1 and so the gradient would be 3. If you have been given a diagram instead of the equation, you'll need to work out the change in y-coordinate divided by the change in x-coordinate. So to do this, you pick any two points on the graph and work out the difference between the two y-coordinates and the difference between the two x-coordinates and then divide your answer for y-coordinates by your answer for x-coordinates. Example: points on line (3,2) and (6,10). Change in y is 10-2=8, change in x is 6-3=3. Gradient is 8/3.

HW
Answered by Hebe W. Maths tutor

22811 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Draw the graph of y=x^2-4x-21


Change the subject of the formula F=(t^2+4b)/c to b.


P (–1, 4) is a point on a circle, centre O which is at the origin. Work out the equation of the tangent to the circle at P. Give your answer in the form y = mx + c


(a) Factorisefully 3a3b+12a2b2 +9a5b3


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences