Solve the differential equation: dy/dx = 6x^2 + 4x + 9
dy/dx = 6x2 + 4x + 9
dy = (6x2 + 4x + 9) dx
integrating gives:
y= (6x3/3) + (4x2/2) + 9x + c
y= 2x3 + 2x2 + 9x + c
If given boundary conditions of y(0)=0 then
0 = 2(0)3 + 2(0)2 +9(0) +c
therefore c=0
so y= 2x3 + 2x2 + 9x
JH
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