Solve the differential equation: dy/dx = 6x^2 + 4x + 9

dy/dx = 6x2 + 4x + 9

dy = (6x2 + 4x + 9) dx 

integrating gives:

y= (6x3/3) + (4x2/2) + 9x + c

y= 2x3 + 2x2 + 9x + c

If given boundary conditions of y(0)=0 then 

0 = 2(0)3 + 2(0)2 +9(0) +c 

therefore c=0 

so y= 2x3 + 2x2 + 9x

JH
Answered by Jack H. Maths tutor

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