How would I solve the equation 25^x = 5^(4x+1)?

You would have to rewrite 25 as 5^2 hence 25^x = (5^2)^x = 5^(2*x).

Then 5^(2x) = 5^(4x+1) and therefore 2x = 4x + 1 hence 2x = -1 hence x = -1 / 2. 

MP

Related Maths A Level answers

All answers ▸

Find the set of values for which: x^2 - 3x - 18 > 0


How can you integrate ln(x) with respect to x?


Via the product rule, or otherwise, differentiate 'y = xsin(x)'.


Differentiate 8x^4 + 2x^2 + 10