Solve the equation x ^2>=3(x + 6)

1. Begin by mulitplying out the bracket on the right hand side of the equation.  x^2=3x+18 2. Now move all of the terms of the equation onto one side by subtracting them     x^2-3x-18=0 3. The quadratic equation can now be solved by factorisation.        (x-6)(x+3)=0 4. To find the final values of x each bracket must be set equal to 0 and solved seperately.      (x-6)=0         x=6           (x+3)=0       x=-3 As this is a quadratic equation we have two final values for x:    x=-3 or x=6

BT

Related Maths GCSE answers

All answers ▸

Solve the simultaneous equations “x^2+y^2=4” and “x=2-y”. What does this tell us about the circle centred on the origin, with radius 2, and the straight line with y-intercept 2 and gradient -1?


How do you add and multiply surds?


Expand and Simplify: (x+2)(x+3)(x−3)


Factorise x^2-7x+12