Solve the equation x ^2>=3(x + 6)

1. Begin by mulitplying out the bracket on the right hand side of the equation.  x^2=3x+18 2. Now move all of the terms of the equation onto one side by subtracting them     x^2-3x-18=0 3. The quadratic equation can now be solved by factorisation.        (x-6)(x+3)=0 4. To find the final values of x each bracket must be set equal to 0 and solved seperately.      (x-6)=0         x=6           (x+3)=0       x=-3 As this is a quadratic equation we have two final values for x:    x=-3 or x=6

BT

Related Maths GCSE answers

All answers ▸

How do you make f the subject of the following a = c/d + e/f


When I multiple two negative numbers together is my answer positive or negative?


Solve x^2+6x+5=0


Work out the value of 27 ^-2/3