Solve the simultaneous equations 3x + 2y = 4 and 4x + 5y = 17

3x + 2y = 4 (equation 1) 4x + 5y = 17 (equation 2) Multiply equation 1 by 2.5, giving 7.5x + 5y = 10 (equation 1) 4x + 5y = 17 (equation 2) Subtract equation 2 from equation 1, giving 3.5x = -7 Therefore, x = -2 Substitute x = -2 back into equation 1, so 3(-2) + 2y = 4 -6 + 2y = 4 2y = 10 Therefore y= 5 Final answer: x=-2, y=5

IG

Related Maths GCSE answers

All answers ▸

Calculate the length of the hypotenuse of a right-angled triangle when the other two sides measure 6cm and 9cm.


What is 25% of 400?


Solve the simultaneous equations for x and y: 2x+4y=-12 and y=-x-2


How do you solve simultaneous equations?