Why is n^0 always 1 and not 0?

Anything raised to the zeroth power is a difficult thing to get your head around. The easiest explanation (not a full proof) is to look at what happens as we go down in powers of n: n^3=nnn        n^2=(n^3)/n=nn       n^1=(n^2)/n=n From that it follows that n^0=(n^1)/n=n/n=1 So n^0=1. I think the easiest way to think about this conceptually is that, although x+0=x, x0=0 while x*1=1. Funny things happen with 0, which is why you should never consider the expression 0^0 as either equal to 0 or 1! (Or not at this level anyway.)

JC

Related Maths GCSE answers

All answers ▸

How do you solve a simultaneous equation by 'substitution'?


Solve the equation x^2-9x+20=0


Find the value of x when x^2-x-6=0


Workout 2 1/7 + 1 1/4