Use implicit differentiation to find dy/dx of: 2(x^2)y + 2x + 4y - cos((pi)y) = 17

Tackle this problem one part at a time: First differentiate 2x²y using the product rule, showing dy/dx(2x²y) = 4xy + 2x²(dy/dx). After this, the remainder of the question is easier, as there are no more mixes of x and y.  dy/dx(2x + 4y - cos((pi)y)) = 2 + 4(dy/dx) + (pi)(dy/dx)sin((pi)y)           Also, dy/dx(17) = 0 Hence the equation you get is: 4xy + 2x²(dy/dx) + 2 + 4(dy/dx) + (pi)(dy/dx)sin((pi)y) = 0 Rearranging, you can see: dy/dx = (-2 - 4xy)/(2x² + 4 + (pi)sin((pi)y))