The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a.
3x-2y=7. y=-3/2x+7/2. mn=-1. m=2/3. m=dy/dx. 2/3=4-b/3-a. 4-b=2-2/3a.b=2/3a+2
