Express 3sinx - 2cosx in the form R(sin(x-a) given R>0 and 0<a<90°. Hence solve 3sinx - 2cosx = 1 in the interval 0<x<360°. What are the maximum and minimum values of 2sinx - 3cosx?

.

CC
Answered by Calem C. Maths tutor

9189 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

given that y = 1 when x = π, find y in terms of x for the differential equation, dy/dx = xycos(x)


Differentiate y = 2x^3 + 6x^2 + 4x + 3 with respect to x.


How do I find the nature of a stationary point


A particle, P, moves along the x-axis. The displacement, x metres, of P is given by 0.5t^2(t^2 - 2t + 1), when is P instantaneously at rest


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences