Differentiate expressions of form Ax^b where A and b are constants and x is a variable

First you have Ax^b where x is a variable.

Then you multiply A and b together with the variable so you have Abx^b

Then you minus 1 from the b which gives you the final answer Abx^(b-1)

RI

Related Maths A Level answers

All answers ▸

Integrate 6/(e^x+2) between 1 and 0


Find dy/dx when y = 2ln(2e-x)


What are the limits of an inverse tan graph.


How would you expand (x+5y)^5?