differentiate (1+2x^2)^(1/2)

This differentiation requires use of the chain rule. The first step is to differentiate the whole thing, treating the bracket as u, so u=1+2x2. Therefore we are differentiating u1/2. This means our first step gives us the value:   1/2*u-1/2     (given student understands simple differentiation) Replacing u this gives us  1/2 *(1+2x2)-1/2   but now we must multiply this by the differential of the inside of the bracket (u=1+2x2) differentiating gives:  du/dx=4x   as the constant term disappears. so putting this back in, you multiply our two answers together to give                          dy/dx = 1/2 *(1+2x2)-1/2 *4x                            = 2x *(1+2x2)-1/2   and so you have your answer.

RS
Answered by Reuben S. Maths tutor

11406 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given a curve has the equation f'(x) = 18x^2-24x-6 and passes through the point (3,40), use integration to find f(x) giving each answer in its simplest form.


make into a cartesian equation= x=ln(t+3) y= 1/t+5


When I integrate by parts how do I know which part of the equation is u and v'?


How do I use the product rule for differentiation?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning