V= 4(h^3 +1)^0.5 - 4, find dv/dh when h=2

V= 4(h3+1)0.5- 4 dV/dh= (4x 0.5) x 3h2 x (h3+1)-0.5  =>  6h2(h3+1)-0.5 Substitute h=2 into dV/dh   => (6x22)x(23+1)-0.5    => 24 x 1/3 = 8

OD

Related Maths GCSE answers

All answers ▸

Work out the value of the following:


Renee buys 5 kg of sweets to sell. She pays £10 for the sweets. Renee puts all the sweets into bags. She puts 250 g of sweets into each bag. She sells each bag of sweets for 65p. Renee sells all the bags of sweets. Work out her percentage profit.


What can I say about the roots of a quadratic equation without actually calculating them?


h^2=25. solve this quadratic equation to find h.