How do I know how many solutions a quadratic equation has?

A quadratic equation is an equation that looks like:

x2 + 4x - 2 = 0.

The general form of this is written as ax2 + bx + c = 0, where a, b and c are all numbers, and x is our unknown variable. In the example above, we would have a = 1, b = 4 and c = -2.

In order to find the number of solutions, we shall split the quadratic equation into 3 cases.

Case 1: 2 unique solutions - eg x2 + 5x + 6 = 0. Has solutions x = 2 and x = 3.

Case 2: 1 repeated solution - eg x2 + 4x + 4 = 0. Has solution x = 2.

Case 3: No solutions - eg x2 + 2x + 4 = 0. Has no solutions.

But how do we know which case we are in? To do this, we take a look at the quadratic formula, which you will hopefully have seen by now. For reference, it gives the solution of the general quadratic ax2 + bx + c = 0 as:

x = [-b ± √(b2 - 4ac)]/2a

where the ± signifies that the two solutions are 

x = [-b + √(b2 - 4ac)]/2a and 

x = [-b - √(b2 - 4ac)]/2a.

In Case 1, this will give two separate answers for x. In Case 2, both answers will be the same.

However, in Case 3 you will likely arrive at an error! This error arises from the fact that we cannot take the square root of a negative number*. This means, that if we are in case 3, then the section √(b2 - 4ac) is the part that is causing problems! As I said, we cannot take the square root of a negative number, so if b2 - 4ac is negative, we have an error, and no solutions.

This is the key to knowing how many solutions we have: 

If b2 - 4ac is positive (>0) then we have 2 solutions.

If b2 - 4ac is 0 then we have only one solution as the formula is reduced to x = [-b ± 0]/2a. So x = -b/2a, giving only one solution.

Lastly, if b2 - 4ac is less than 0 we have no solutions. 


How many solutions does x- 3x + 2 = -1 have?

1) Rearrange to fit the general formula: x2 - 3x + 3 = 0. So a = 1, b = -3 and c = 3.

2) Use the formula: b- 4ac = (-3)- 4(1)(3) = 9 - 12 = -3.

3) As b- 4ac < 0, we have no solutions.

So there you have it! Please get in touch if you require any further assistance.

For those interested/advanced students: Technically, you CAN take a square root of a negative number. It's beyond the scope of a GCSE course, so if you're confused by anything after this, don't worry! First of all though, I'll explain why nobody has told you this yet.

Imagine that I asked you to give me the answer to 7 ÷ 3, but you could only use whole numbers. The equation 7 ÷ 3 is equal to 2.33..., but this is not a whole number! So no whole number solutions exist. If I allowed you to use fractions, you could tell me that 7 ÷ 3 is 7/3 or 2 and 1/3.

The same idea applies to the problem here. We only have Real numbers (that is, fractions, decimals, whole numbers and "irrational" numbers such as pi) to deal with the question, and if you are asked to take the square root of a negative number, there are no Real solutions! 

A solution does exist in the "Imaginary" numbers. You don't know about these numbers yet (just like you didn't know about fractions at first). You will learn more about this in A level Further Maths, or perhaps at University, but if this sounds interesting please do check them out via Google.

If b- 4ac < 0 then there are no "Real" solutions. 

However, for your GCSEs, saying that there are no solutions will be good enough for the exam!

Nathan C. A Level Maths tutor, GCSE Maths tutor, 13 plus  Maths tutor...

2 years ago

Answered by Nathan, a GCSE Maths tutor with MyTutor

Still stuck? Get one-to-one help from a personally interviewed subject specialist


£18 /hr

Kai A.

Degree: Physics (Masters) - Bristol University

Subjects offered:Maths, Physics+ 2 more

Further Mathematics

“Hi! My name is Kai and I study physics at Bristol. I am happy to tutor in maths, further maths, physics and the PAT.”

MyTutor guarantee

£18 /hr

Ellen L.

Degree: History (Bachelors) - Durham University

Subjects offered:Maths, History+ 2 more

-Personal Statements-

“About me: I am a History student at Durham University and have always loved learning about what has happened in the past!  I am friendly, understanding and always more than happy to help. Teaching children as young as three at my the...”

MyTutor guarantee

£18 /hr

Aravin S.

Degree: Economics (Bachelors) - Bristol University

Subjects offered:Maths


“About Me: I am an economics student at Bristol University. I have always had a real passion and love for maths and hope that my tutorials will instil that love in you too. I am very patient and friendly. I have a lot of previous exper...”

About the author

Nathan C.

Currently unavailable: until 01/01/2017

Degree: Mathematics (Bachelors) - Warwick University

Subjects offered:Maths


“3rd Year Maths student at Warwick with lots of experience tutoring all ages! Prompt replies to all messages and eager to help.”

MyTutor guarantee

You may also like...

Other GCSE Maths questions

What can I do to revise maths?

If x^2 = 16, why isn't the answer just x = 4?

Expand and simplify the following; (2 + 3^0.5)^2 - (2 - 3^0.5)^2

How do I simplify the equation 4x + 5x -2 - 2x + 7?

View GCSE Maths tutors

We use cookies to improve your site experience. By continuing to use this website, we'll assume that you're OK with this. Dismiss