Solve y=x^2 - 1, y=5 - x

x= -3, y= 8 and x= 2, y= 3
(1) 5 - x = x^2 - 1(2) x^2 + x - 6 = 0(3) (x+3)(x-2) = 0(4) when x = -3, y= 5 - (-3) = 8(5) when x = 2, y= 5 -(2) = 3

TB
Answered by Tamim B. Maths tutor

3633 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What is the nth-term of this sequence? 29, 26, 23, 20, 17...


Solve 3(x-2)=21


Why is anything to the power 0 equal 1?


Sam uses 140g of flour to make 12 cakes. How much flour will Sam need to make 21 cakes?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning