Solve y=x^2 - 1, y=5 - x

x= -3, y= 8 and x= 2, y= 3
(1) 5 - x = x^2 - 1(2) x^2 + x - 6 = 0(3) (x+3)(x-2) = 0(4) when x = -3, y= 5 - (-3) = 8(5) when x = 2, y= 5 -(2) = 3

TB
Answered by Tamim B. Maths tutor

3825 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve x^2 = 4(x – 3)^2


Expand 2a (4 + a)


Solve: x^2-x-6 using factorisation.


Factorise 5a – 3a^2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning