Calculate the acceleration of particle thats velocity changes from 20ms^-1 to 40ms^-1 in 5 seconds, assuming its constant.

Acceleration is the rate of change of velocity, so we subtract the final velocity from the initial velocity and divide it by the time taken for the change. In this case the acceleration is (40-20)/5 = 4ms^-2. This means that each second, the velocity of the particle is increasing by 4ms^-1

OF
Answered by Orlando F. Physics tutor

4025 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

What is the wavelength of a wave?


What does a velocity-time graph represent?


Why does resistance increase with temperature?


Explain Ohm's Law


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning