a.) simplify and expand (x+3)(2x+5) b.) differentiate (x+3)(2x+5) c.) where does this function intercept the x and y axis? d.) does this function have any turning points? if so where?

a.) simplify and expand (x+3)(2x+5) Expand using "crab claw" (better known as foil) => 2x^2 + 5x + 6x + 15 Simplify => 2x^2 +11x + 15 b.) differentiate (x+3)(2x+5) Using part a,  dy/dx= 4x +11 c.) where does this function intercept the x and y axis? Factorise answer to part a.  Since we had to expand the factorised answer to part a, we know that our function crosses the x axis when x= -3 and x=-5/2 or -2.5 Substitute value of x= 0 into function to find y intercept => y=15 d.) does this function have any turning points? if so where? dy/dx=0 4x+11=0 4x=-11 x=-11/4 y=-1/8.  Therefore it has a turning point at (-11/4, -1/8)

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Answered by Calvin H. Maths tutor

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