Differentiate sin(x^3) with respect to y
For this we must use the chain rule. We start by defining x3 as a new variable, u = x3 Can then rewrite the expression as y = sin(u) Chain rule tells us that dy/dx = (dy/du)(du/dx) We can calculate these individidually. dy/du = cos(u) du/dx = 3x2 Finally we can then say, dy/dx = dy/du * du/dx = cos(u) * 3x2 = 3x2cos(x3)
LB
Related Maths A Level answers
All answers ▸How do you take the derivative of a^x ?
Use integration by parts to integrate the following function: x.sin(7x) dx
Find the binomial expansion of (4-8x)^(-3/2) in ascending powers of x, up to and including the term in x^3. Give each coefficient as a fraction in its simplest form. For what range of x is a binomial expansion valid?
The element of a cone has length L. For what height H (with respect to L) will the volume of the cone be the largest?