Solve the two equations: Equation 1: 2a - 5b = 11 Equation 2: 3a + 2b = 7

Firstly, you should aim to eliminate one of the unknown values. As b is positive and negative in each equation, this would be a good value to eliminate. Both equations would have to be multiplied to cancel out one of the values. For example, if equation 1 is multiplied by 2 and eqution 2 is multiplied by 5 you get:

Equation 1: 4a-10b= 22         Equation 2: 15a+ 10b= 35

Then add the two new equations together to cancel out b and simplify, which leaves you with:

19a= 57 therefore   a= 3

Then substitute a with 3 in equation 1 or 2 to find out the value of b. For example, if substituted into equation 1 you get:

(2 x 3) -5b=11   therefore  b=-1 

IH
Answered by Ikraan H. Maths tutor

5909 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

8 pens in a bag, 3 blue, 5 red. 2 taken out at random, without replacement. Probability they are the same colour?


Solve the simultaneous equations for x and y: 2x - 3y + 4 = 0 , x - 2y + 1 = 0.


How do you complete the square? example: x^2 + 8x + 13=0


What is the Pythagoras Theorem?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences