Differentiate y=(3x-1)/(2x-1)
First, recognise that the function is a fraction and recall the quotient rule. y=u/v dy/dx=(vu'-uv')/v2, where u' and v' is the derivative of u and v respectively. Then, apply the rule. u=3x-1, v=2x-1 u'=3, v'=2 dy/dx=[3(2x-1)-2(3x-1)]/(2x-1)2 Finally, simplify the expression. dy/dx=1/(2x-1)2
