Express 9^(3x + 1) in the form 3^y , giving y in the form ax + b, where a and b are constants.
9^ (3x + 1)
We know that 3 to power of 2 equals 9. 3x3 = 3^2 = 9,
= 3^ (2 * [3x + 1])
We simply the term because 2 * [3x + 1] = 6x + 2
= 3^ ( 6x + 2)
This term is in the form of 3^ y, so we know that y = 6x + 2 by comparing like terms.
y = 6x + 2 a = 6, b = 2
WL
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