Find the 12th term and the sum of the first 9 terms on the following Arithmetic Progression: a = 2 and d = 3
12th term = a + (12 - 1)*d = 2 + 11(3) = 35
Sum (9) = 9/2 [2(2) + (9 - 1)*3] = 9/2 [28] = 252/2 = 126
ER
12th term = a + (12 - 1)*d = 2 + 11(3) = 35
Sum (9) = 9/2 [2(2) + (9 - 1)*3] = 9/2 [28] = 252/2 = 126
