Differentiate with respect to x: y = ln(x^2+4*x+2).
Let u = x2+4x+2 so y = ln(u).
Then dy/du = 1/u and du/dx = 2x+4.
Using the chain rule we have:
dy/dx = (dy/du)*(du/dx)
= (1/u)*(2x+4)
= (2x+4)/(x2+4x+2).
OL
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I already done this.
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