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What is the indefinite integral ∫5exp(3-4x)dx ?
∫ 5e
3-4x
dx=5∫e
3
e
-4x
dx=5e
3
∫e
-4x
d=5e
3
[(-1/4)e
-4x
]=-(5/4)e
3
e
-4x
=-(5/4)e
3-4x
AM
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Alexandros M.
•
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