4x^2 + 8x + 3 can be written in the form a(x + b)^2 + c where a, b and c are whole numbers. Work out the values of a, b and c.

Factorise 4x² + 8x + 3 = 4(x² + 2x + 3/4) divide the coefficient of x by 2: 2/2=1 Now x²+2x = (x+1)²-1² = (x+1)²-1 Hence, 4((x+1)²-1+3/4) = 4(x+1)²-1 which is of the form a(x + b)² + c So a=4, b=1, c=-1