y' = (2x)/(y+1). Solve for y.
y' = dy/dx = (2x)/(y+1) Separate x's and y's in this case.
y + 1 dy = 2x dx Now integrate both sides.
(y2)/2 + y = (2x2)/ 2 + C Don't forget the constant.
(y2)/2 + y = x2 + C
DM
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