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y' = (2x)/(y+1). Solve for y.

y' = dy/dx = (2x)/(y+1) Separate x's and y's in this case.

y + 1 dy = 2x dx Now integrate both sides.

(y²)/2 + y = (2x²)/ 2 + C Don't forget the constant.

(y²)/2 + y = x² + C

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Answered by Daniel M. • Maths tutor

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