Use the chain rule to show that, if y = sec(x), then dy/dx = sec(x)tan(x).

First, write y in terms of cos(x). We are familiar with cos(x) and know how to differentiate it. We know that sec(x) = 1/cos(x) = (cos(x))-1.  Next, find dy/dx in terms of cos(x) and sin(x). Again, we are familiar with cos(x) and sin(x) and will be able to get the answer in terms of sec(x) and tan(x) later.  Time to use the chain rule. Multiply by the current power, reduce the current power by 1 and multiply by the differential of what is inside the brackets. Hence, we end up with: dy/dx = -1 x (cos(x))-2  x -sin(x) = sin(x)/cos(x) because the minus signs cancel each other. Finally, we know that we need to get dy/dx in terms of sec(x) and tan(x), so we need to look for a way to achieve this. We can get this by separating sin(x)/cos(x) into sin(x)/cos(x) x 1/cos(x). Using our knowledge of the definitions of sec(x) and tan(x), we can see that this is just sec(x) x tan(x), as required.

NL
Answered by Noah L. Maths tutor

14498 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

For sketching the graph of the modulus of f(x) (in graph transformations), why do we reflect in the x-axis anything that is below it?


Find the total area enclosed between y = x^3 - x, the x axis and the lines x = 1 and x= -1 . (Why do i get 0 as an answer?)


When and how do I use integration by parts?


(Core 2) Show that the region bounded by the curve y = 7x+ 6 - (1/x^2), the x axis and the lines x = 1 and x = 2 equals 16


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences