Using the product rule, differentiate: y = (x^2 - 1)(x^3 + 3).
y=(x2-1)(x3+3) let u=x2-1 u'=2x let v=x3+3 v'=3x2 uv'+u'v=(x2-1)(3x2)+(2x)(x3+3) =(3x4-3x2)+(2x4+6X) =5x4-3x2+6x
y=(x2-1)(x3+3) let u=x2-1 u'=2x let v=x3+3 v'=3x2 uv'+u'v=(x2-1)(3x2)+(2x)(x3+3) =(3x4-3x2)+(2x4+6X) =5x4-3x2+6x
