Solve the following pair of simultaneous equations 1)x+3y=11 2)3x+y=9

Rearrange equation 2 to make y the subject, then substitute the y expression into equation 1 and collect like terms: 3x+y=9 -->> y=9-3x x+3y=11 -->> x+3(9-3x)=11 -->> x+27-9x=11 -->> 27-11=8x -->> 16=8x -->> 16/8=x -->> x=2 Now that the x term is determined this value can be substituted into either equation 1, equation 2 or the rearranged equation 2 (the rearranged equations is ideal in this case since y is the subject and the then re-arrange is done all we need to do is substitute in the x term): y=9-3x -->> y=9-(3*2) -->> y=9-6 --> y=3 Answer: (2,3)

TD
Answered by Tutor94832 D. Maths tutor

7866 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Harry drives from Exeter to London in 4 hours at an average speed of 70km/h. Ron drives from Exeter to London in 5 hours. (a) Assuming Ron took the same route as Harry, calculate Ron's average speed.


solve two variables quadratic equation system 2x-y=1 10x^2-y^2-x+1=0


The area of a square is 49cm^2. The perimeter of the square is equal to the circumference of a circle. what is the radius of the circle?


Write the following in their simplest form: a) 8^0 b) 64^(2/3) c) 0.54545454...


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning