Solve the following simultaneous equations: A. 2x-2y=18 and B. 3x+y=23

Step 1: Rearrange one equation to make y the subject. In equation B, we can move the 3x to the other side, making it negative and making the equation y=23-3xStep 2: Substitute our new value for y into equation A: 2x-2(23-3x)=18Step 3: Find the value of x by solving equation A: 2x-46+6x=18, 8x-46=18, 8x=64, x=8Step 4: Substitute our value for x into equation B to find the value of y: 3(8)+y=23, 24+y=23, y=-1Step 5: Substitute both values into equation A to confirm that these are correct: 2(8)-2(-1) = 16+2 = 18

SM
Answered by Sahil M. Maths tutor

4344 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

What if my equation doesn't factorise?


Solve simultaneously: 2x + y = 18 and x - y = 6


You are given sets A: {2,4,6,8,10,12} and B: {1,3,5,7,9,11} explain why A∩B = ∅


Write x^2+4x-12 in the form (x+a)^2+b where a and b are constants to be determined.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning