Differentiate "sin(2x)"
Sinx differentiates to give cosx.
We then multiply this by the differential of "2x."
Which equals 2.
Our answer therefore is "2cos(2x)."
CB
Sinx differentiates to give cosx.
We then multiply this by the differential of "2x."
Which equals 2.
Our answer therefore is "2cos(2x)."