make a the subject of p = (3a+5)/(4-a)

so step 1) remove the denominator by multiplying (4-a) by p. Therefore obtaining p(4-a) = 3a+5. step 2) multiply out to get 4p-ap = 3a+5 step 3) have all the a's on one side, and non a's on other side. therefore: 4p-5 = 3a+ap step 4) factor out the a's. 4p-5 = a(3+p) step 5) make a = (4p-5)/(3+p) 

JW
Answered by Jamie W. Maths tutor

9885 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand and simplify (x-5)(3x+3)


How do you solve simultaneous equations?


There are 895 litres of petrol in Mr Turners petrol tank, he uses 19.7 litres of petrol a day. Estimate the number of days it will take him to use all the petrol in the tank.


Solve the simultaneous equations : x^2 + y^2 = 13 and x = y - 5 .


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences