A Curve has parametric equation x=2sin(t), y= 1+cos(2t), -pi/2<=t<=pi/2. a) Find dy/dx when t=pi/3. b) Find the Cartesian equation for the curve in form y=f(x), -k<=x<=k. c) Find the range of f(x)
x=2sin(t), y=1+cos(2t)
a) By chain rule, dy/dx = (dy/dt)/(dx/dt)
dy/dt = -2sin(2t), dx/dt= 2cos(t)
dy/dx= -sin(2t)/cos(t)
dy/dx=-2sin(t)cos(t)/cos(t)
dy/dx=-2sin(t)
when t = pi/3,
dy/dx= -sqrt(3)
b) dy/dx = -2sin(t)= -x
y= -x^2/2
k=2 as x=2sin(t) has max and min values at 2, -2
c) Draw a sketch
Sketch shows symmetrical quadratic with min value 0, max values of 2.
0<=f(x)<=2
MB
Related Maths A Level answers
All answers ▸If f(x) = (3x-2) / x-5 x>6, find a.) ff(8) b.) the range of f(x) c.) f^-1(x) and state its range.
A curve, C, has equation y =(2x-3)^5. A point, P, lies on C at (w,-32). Find the value of w and the equation of the tangent of C at point, P in the form y =mx+c.
Given two functions x = at^3 and y = 4a, find dy/dx
At time t = 0, a particle is projected vertically upwards with speed u m s–1 from a point 10 m above the ground. At time T seconds, the particle hits the ground with speed 17.5 m s–1. Find the value of u and T and evaluate the model. (AS mechanics)