Find dy/dx in terms of t of the parametric equations x=4e^-2t, y=4 - 2e^2t

x=4e-2t, y=4-2e2t

dy/dx = dy/dt * dt/dx

dy/dt = -4e2t

dx/dt = -8e-2t           dt/dx = -1/8 * e2t

dy/dx = (-4e2t)(-1/8 * e2t) = 1/2 * e4t

dy/dx = 0.5e4t

 

JM
Answered by Josh M. Maths tutor

5932 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve has equations: x=2sin(t) and y=1-cos(2t). Find dy/dx at the point where t=pi/6


Given that y= x^(-3/2) + (1/2)x^4 + 2, Find: (a) the integral of y (b) the second differential of y


How do you prove two straight lines intersect?


Find the derivative of the function y = (2x + 12)/(1-x)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning